9m^2-16=m

Solution for 9m^2-16=m equation:

9m^2-16=m

We move all terms to the left:

9m^2-16-(m)=0

We add all the numbers together, and all the variables

9m^2-1m-16=0

a = 9; b = -1; c = -16;
Δ = b2-4ac
Δ = -12-4·9·(-16)
Δ = 577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{577}}{2*9}=\frac{1-\sqrt{577}}{18}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{577}}{2*9}=\frac{1+\sqrt{577}}{18}
$